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  • #41
    Originally posted by ckBejug
    Cake.

    Turn on each light switch for a few minutes and go into the room after each one and feel the bulb. Whenever you feel the warm bulb you know you got the right light switch.
    well you could only go into the room once, not 3 times - but you got the hard part - flip 2nd for a few min, flick off, then flick 3rd on - if its cold off its 1st, if its hot off its 2nd if its on its 3rd - you are very good at these though, ill give you my hardest -

    A wizard captures 3 people. He puts them all in a room, and he blindfolds them. He then places a hat on each one of their heads, and says, when I remove your blindfolds, whatever one of you tells me what color hat you have on your head and why (guesses = death even if your right) you will be spared and eveyone else will die. There are only 2 colors of hats, white and blue, and the only rule of the hats is there cannot be three white hats used. There can be any other combination of hats on your heads. You can also not communicate in any way with the other people, or see the color of your own hat. If you do you die (no taking it off or looking at reflections etc..) He removes the blindfolds and you see the two other guys are each wearing blue hats. After several minutes, you stand up and say what color hat you have on your head and why. What did you say? Remember you are competing with those two other guys who also want to live.

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    • #42
      Originally posted by One-Way
      A man and a woman were driving in their car when it broke down. The man decided to go for help at a gas station a few miles back. He made sure nobody was in the car, rolled all the windows up, and locked all of the sedan's doors. He went off, but when he came back, his wife was dead, and there was a stranger in the car. No physical damage was done to the car, so how did the stranger get in?
      I want to say she died of suffocation or overheated in the car but that wouldn't explain the stranger. Was the wife pregnant? She had the baby but died delivering it and I guess the baby is a 'stranger' since the husband hasn't seen it yet?
      The test of a first-rate intelligence is the ability to hold two opposing ideas in mind at the same time and still retain the ability to function. -- F. Scott Fitzgerald

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      • #43
        ^ Ugh. Yeah, you're right, lol.

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        • #44
          well you could only go into the room once, not 3 times - but you got the hard part - flip 2nd for a few min, flick off, then flick 3rd on - if its cold off its 1st, if its hot off its 2nd if its on its 3rd - you are very good at these though, ill give you my hardest -

          A wizard captures 3 people. He puts them all in a room, and he blindfolds them. He then places a hat on each one of their heads, and says, when I remove your blindfolds, whatever one of you tells me what color hat you have on your head and why (guesses = death even if your right) you will be spared and eveyone else will die. There are only 2 colors of hats, white and blue, and the only rule of the hats is there cannot be three white hats used. There can be any other combination of hats on your heads. You can also not communicate in any way with the other people, or see the color of your own hat. If you do you die (no taking it off or looking at reflections etc..) He removes the blindfolds and you see the two other guys are each wearing blue hats. After several minutes, you stand up and say what color hat you have on your head and why. What did you say? Remember you are competing with those two other guys who also want to live.
          __________________
          thats easy

          Assume I'm person A the the people with Blue hats are Person B and C

          If my hat was white person B would see one white and one blue hat. Preson B konws that if his hat was white then Person C would see two hats and would konw the color of his hat (blue).

          Since nobody niether Person A or B can figure out the color of their hat that means that all of our hats are blue

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          • #45
            Originally posted by Harut82
            thats easy

            Assume I'm person A the the people with Blue hats are Person B and C

            If my hat was white person B would see one white and one blue hat. Preson B konws that if his hat was white then Person C would see two hats and would konw the color of his hat (blue).

            Since nobody niether Person A or B can figure out the color of their hat that means that all of our hats are blue
            well played

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            • #46
              There are 3 black hats and 2 white hats in a box. Three men (we will call them A, B, & C) each reach into the box and place one of the hats on his own head. They cannot see what color hat they have chosen.

              The men are situated in a way that A can see the hats on B & C's heads, B can only see the hat on C's head and C cannot see any hats.

              When A is asked if he knows the color of the hat he is wearing, he says no.
              When B is asked if he knows the color of the hat he is wearing he says no.
              When C is asked if he knows the color of the hat he is wearing he says yes and he is correct.

              What color hat and how could he know?

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              • #47
                Black, C could see the box and both white hats were in it??

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                • #48
                  Originally posted by DZB84
                  well you could only go into the room once, not 3 times - but you got the hard part - flip 2nd for a few min, flick off, then flick 3rd on - if its cold off its 1st, if its hot off its 2nd if its on its 3rd - you are very good at these though, ill give you my hardest -
                  You didn't really mention that you were only allowed to go into the room just once. Anyway I'm glad my answer still works.
                  The test of a first-rate intelligence is the ability to hold two opposing ideas in mind at the same time and still retain the ability to function. -- F. Scott Fitzgerald

                  Comment


                  • #49
                    Originally posted by Harut82
                    There are 3 black hats and 2 white hats in a box. Three men (we will call them A, B, & C) each reach into the box and place one of the hats on his own head. They cannot see what color hat they have chosen.

                    The men are situated in a way that A can see the hats on B & C's heads, B can only see the hat on C's head and C cannot see any hats.

                    When A is asked if he knows the color of the hat he is wearing, he says no.
                    When B is asked if he knows the color of the hat he is wearing he says no.
                    When C is asked if he knows the color of the hat he is wearing he says yes and he is correct.

                    What color hat and how could he know?
                    If A saw two white hats on B and C then he he would have said he was wearing a black hat because there are only 2 white hats. He said he didn't know so that means he must have seen a black hat and a white hat or two black hats. B knows that A must have seen a black hat and a white hat or two black hats (or else he would have answered). B must have seen a black hat on C's head or else he would have answered. Since he saw a black hat he doesn't know if he has a black hat or a white hat, so he doesn't answer. Since B doesn't answer either it means C is wearing a black hat and C knows this because he is smart and figured out what I just said.

                    Right?
                    Last edited by ckBejug; 06-15-2005, 03:52 PM.
                    The test of a first-rate intelligence is the ability to hold two opposing ideas in mind at the same time and still retain the ability to function. -- F. Scott Fitzgerald

                    Comment


                    • #50
                      Originally posted by ckBejug
                      If A saw two white hats on B and C then he he would have said he was wearing a black hat because there are only 2 white hats. He said he didn't know so that means he must have seen a black hat and a white hat or two black hats. B knows that A must have seen a black hat and a white hat or two black hats (or else he would have answered). B must have seen a black hat on C's head or else he would have answered. Since he saw a black hat he doesn't know if he has a black hat or a white hat, so he doesn't answer. Since B doesn't answer either it means C is wearing a black hat and C knows this because he is smart and figured out what I just said.

                      Right?

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